# [Tutor] list comprehension question

Tom Musgrove tommusgrove__ at hotmail.com
Tue Jun 1 18:43:45 EDT 2004

```>Was that a typo?

Hi Blake, it was indeed a typo, new to the whole python thing...

Here is the solution I came up with

>>>ListAUniqueEdges = [(1,5), (2,6), (3,7), (8,9)]
>>>ListBUniqueEdges = [(2,7), (3,5), (1,6), (10,11)]
>>>NewDict = {}
>>>for k,v in ListAUniqueEdges:
>>>	listTemp = []
>>>	for m,n in ListBUniqueEdges:
>>>		if((k==m)or(k==n)or(v==m)or(v==n)): #seems there should be a better
>>>method here
>>>			if (listTemp == []) :
>>>				listTemp = [(m,n)]
>>>			else:
>>>				listTemp.extend([(m,n)])
>>>	NewDict[(k,v)] = listTemp
>>>
>>>NewDict
{(3,7): [(2,7), (3,5)], (2,6): [(2,7), (1,6)], (8,9): [], (1,5):[(3,5),
(1,6)]}
>>>

So, it seems to work ok

I'd be interested if there is a 'better' or more elegant way.  Especially
the

if((k==m)or(k==n)or(v==m)or(v==n))

(I tried (k or v) == (m or n) but didn't give the result I'd hoped for...)

>I can do it with a list comprehension, but I'ld like to see
>what you came up with first...
>
>Later,
>Blake.
>

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