[Tutor] Re: Checking for int only

[K J]

I tried what you said and it work good but when you picked a different  char
other than an int it would just say Please choose an number: and if you
messed up twice then it would say that is not an option. So I did some
fooling around with it and came up with this so that it will say that is not
an option the first time.
So thanks for the help.

number = raw_input("Please choose an number: ")


while True:
    try:
        number = int(number)
        break
    except:
        print '  That is not an option.'
        number = raw_input("Please choose an number: ")

----- Original Message -----
From: Andrei <project5 at redrival.net>
To: <tutor at python.org>
Sent: Monday, June 28, 2004 3:13 PM
Subject: [Tutor] Re: Checking for int only


> K J wrote on Mon, 28 Jun 2004 15:07:44 -0400:
>
> > How do you test for something to make sure that it is an int and not
anything else
> > so that when you ask them to enter a number they can only enter a number
and
> > not any other character.
>
> Use try-except:
>
> while True:
>     number = raw_input('Integer: ')
>     try:
>         number = int(number) # will fail if the input is non-numerical
>         break # stop endless loop
>     except: # int() failed -> not an integer
>         print '  That was not an integer.'
>
> Above is assuming that you mean 'integer' when you write 'number'. If you
> mean to include floats, try float() instead of int().
>
> --
> Yours,
>
> Andrei
>
> =====
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