[Tutor] strange variable problem

[Dave S]

Please excuse my poor codeing ... but I have a problem.

ftseptr is setup as a global variable, value -1,
yftseptr is setup as a global variable, value 0

When I execute the calling script I get ....

============================== RESTART ================================
 >>>
Analizing directory ... 20040429
0

Traceback (most recent call last):
  File "/home/dave/gg/gg.py", line 72, in -toplevel-
    gg()
  File "/home/dave/gg/gg.py", line 62, in gg
    file2datacore2(stockdir+dir+'/'+file,syncerr)
  File "/home/dave/gg/gg.py", line 40, in file2datacore2
    
ggdatacore2.add(datalist[i+1],datalist[i+3],datalist[i+5],datalist[i+6],datalist[i+7],datalist[i+8],datalist[i+9],datalist[i+10],datalist[i+11],datalist[i+12],datalist[i+13],syncerr)
  File "/home/dave/gg/ggdatacore2.py", line 30, in add
    print ftseptr
UnboundLocalError: local variable 'ftseptr' referenced before assignment
 >>>

Where the 0 after Analizing directory is from yftseptr, but ftseptr 
causes an exception - no assigned.
They were both assigned at the same time.

Can anyone help

Thanks

Dave

-------------------------------------------------------------------------------------------------------------

The code causing problems ....

import gglogger


ftsedata=[]
yftsedata=[]

ftsedload={}

ftseptr=-1  # Pointer into ftsedata list
yftseptr=0

for i in range(110):

    ftsedata.append(ftsedload)
    yftsedata.append(ftsedload)


def add(id,mid,pence,pc,bid,offer,open,high,low,close,volume,syncerr):

    # Data cookie - is a list
    # [num consecutive loads,bad data counter,bad cycle counter]
    print yftseptr   # These are test prints where I found the problem ;-)
    print ftseptr

   
    try:
        if ftseptr==-1: # If ftseptr==-1 get cookie from ftsedata
            cookie=yftsedata[yftseptr][id][0]
        else:
            cookie=ftsedata[ftseptr][id][0]
    except KeyError:
        cookie=[0,0,2]  # OK no previous id ... start of new record
        gglogger.log('!!','ggdatacore2','New ftse company '+id)