[Tutor] Function problem

[Eri Mendz]

On Fri, 5 Nov 2004, Danny Yoo wrote:
>
> On Fri, 5 Nov 2004, Eri Mendz wrote:
>
>> The problem of my script below is in the proceed function: if Y is
>> selected, instead of staying in the option menu, the program just shows
>> the option menu then exits.
[...]

> The breaks cause us to jump out of the while loop if either temperature
> choice gets selected.
>
> I'm guessing that you're using a C switch statement idiom.  But since that
> idiom isn't applicable in Python, you should just drop them.
>

Got it working now, thanks for the tip. Indeed the break keyword is the
culprit. Here is the corrected code:

import sys

def print_options():
       print '''
       THIS IS A TEMPERATURE CONVERSION PROGRAM.
       Options:
       [C] - convert to Celsius
       [F] - convert to Fahrenheit
       [P] - print options
       [Q] - quit
       '''
print_options()

def f2c(ctemp):
       return (9/5.0)*ctemp + 32

def c2f(ftemp):
       return (ftemp - 32) * 5/9.0

def proceed():
       proceed = raw_input("do another conversion? [Y|N]: ")
       if proceed == 'y' or proceed =='Y':
           print_options()
       else:
           confirmQuit()

def confirmQuit():
       ask = raw_input("Really quit program? [Y|N]: ")
       if ask == 'y' or ask == 'Y' or ask == 'ye' or ask == 'yes':
           sys.exit("bye")
       else:
           print_options()

# begin
while 1:
       choice = raw_input("select options: ")
       if choice == 'c' or choice == 'C':
           try:
               getftemp = int(raw_input("enter fahrenheit temperature: "))
               print "temp in C is: ", c2f(getftemp)
               proceed()
           except ValueError:
               print "error: not a valid input!"
  	     print_options()		# new added: return to main menu
#        break
       elif choice == 'f' or choice == 'F':
           try:
               getctemp = int(raw_input("enter centigrade temperature: "))
               print "temp in F is: ", f2c(getctemp)
               proceed()
           except ValueError:
               print "error: not a valid input!"
               print_options()		# ditto
#        break
       elif choice =='p' or choice == 'P':
           print_options()
       elif choice =='q' or choice == 'Q':
           confirmQuit()
       else:
           print "invalid option"
           print_options()		# ditto

print "bye"

How do i make the program accept decimal numbers, not just integers?
Inputting the former is caught by the exception and i want to correct
that. I also want to use regular expression for the Y|N portion; e.g.,
something like if ask == [Y|y|ye|yes] or ask == [N|n|no|nope]... to that
effect. Any help is appreciated.

-- 
Regards,
Eri Mendz
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