[Tutor] What's the invaild syntax? Error message and relative code supplied.

[python-tutor@toddmaynard.com]

Remember this problem from yesterday?

Take a look at the line before the one you are getting the error on.
And count the ('s and the )'s.

--Todd



On Sunday 31 July 2005 07:38 pm, Nathan Pinno wrote:
> What the invalid syntax? Here is the error message:
> SyntaxError: invalid syntax
>   File "D:/Python22/grades.py", line 66
>     which = which-1
>         ^
> SyntaxError: invalid syntax
>
> Here is the code:
>
> max_points = [25,25,50,25,100]
> assignments = ['hw ch 1','hw ch 2','quiz   ','hw ch 3','test']
> students = {'#Max':max_points}
>
> def print_menu():
>     print "1. Add student"
>     print "2. Remove student"
>     print "3. Print grades"
>     print "4. Record grade"
>     print "9. Exit"
>
> def print_all_grades():
>     print '\t',
>     for i in range(len(assignments)):
>         print assignments[1],'\t',
>     print
>     keys = students.keys()
>     keys.sort()
>     for x in keys:
>         print x,'\t',
>         grades = students[x]
>         print_grades(grades)
>
> def print_grades(grades):
>     for i in range(len(grades)):
>         print grades[i],'\t\t',
>     print
>
> def choice():
>     return int(raw_input("Menu Choice: "))
>
> def school():
>     return raw_input("Student: ")
>
> while 1:
>     print_menu()
>     menu_choice = choice()
>     if menu_choice == 1:
>         print "Add student"
>         name = school()
>         students[name] = [0]*len(max_points)
>     elif menu_choice == 2:
>         print "Remove student"
>         name = school()
>         if students.has_key(name):
>             del students[name]
>         else:
>             print "Student: ",name," not found."
>     elif menu_choice == 3:
>         print_all_grades()
>
>     elif menu_choice == 4:
>         print "Record Grade"
>         name = school()
>         if students.has_key(name):
>             grades = students[name]
>             print "Type in the number of the grade to record"
>             print "Type in a 0 (zero) to exit"
>             for i in range(len(assignments)):
>                 print i+1,' ',assignments[i],'\t',
>             print
>             print_grades(grades)
>             which = 1234
>             while which != -1:
>                 which = int(raw_input("Change which Grade: ")
>                 which = which-1
>                 if 0 <= which < len(grades):
>                     grade = int(raw_input("Grade: ")
>                     grades[which] = grade
>                 elif which != -1:
>                     print "Invalid Grade Number"
>             else:
>                 print "Student not found"
>     elif menu_choice == 9:
>         break
>     else:
>         print "That's not a choice!"
> print "Goodbye."
>
> Thanks for the help in advance!
> Nathan
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