[Tutor] Sorting by numbers

[Kent Johnson]

Jonas Melian wrote:
> :( I get
>  >>> modes
> [['85', '640x480'], ['85', '800x600'], ['85', '1024x768'], ['85', 
> '1280x1024'], ['70', '1600x1200'], ['60', '1920x1440']]
> please help!
> 
> 
>>Solution:
>>modes.sort(key=lambda item: int(item[1].split('x')[0])) # 2.4
>>modes.sort(lambda x, y: cmp(int(x[1].split('x')[0]), 
>>int(y[1].split('x')[0]))) #2.3.5

OK, you want to sort first by frequency, then by size, in descending order. So your key should include both frequency and size and you should include the reverse=True argument to sort. How about

modes.sort(key=lambda item: (int(item[0], int(item[1].split('x')[0])), reverse=True)
?

>>>From an input as this:
>>
>>>Standard timing 0: 85 Hz, 640x480
>>>Standard timing 1: 85 Hz, 800x600
>>>Standard timing 2: 85 Hz, 1024x768
>>>Standard timing 3: 85 Hz, 1280x1024
>>>Standard timing 4: 70 Hz, 1600x1200
>>>Standard timing 5: 60 Hz, 1920x1440
>>>
>>>I want to get columns 3 and 5 for sort them from mayor mo minor, so:
>>>
>>>85 1280x1024
>>>85 1024x768
>>>85 800x600
>>>85 640x480
>>>70 1600x1200
>>>60 1920x1440
>>>
>>>------
>>>modes = []
>>>i = 3; j = 5  # Columns for get
>>>for ln in data:
>>>  if ln.startswith('Standard'):
>>>     modes.append(ln.split()[i:j+1:j+1-i-1])

Alternately you could just build the list in the format you need it for correct sorting. This might be a bit more readable:

modes = []
for ln in data:
   if ln.startswith('Standard'):
       _, _, _, freq, _, dim = ln.split()
       dim = map(int, dim.split('x'))
       modes.append( (freq, dim) )

modes.sort(reverse=True)
for freq, dim in modes:
 print '%s %dx%d' % (freq, dim[0], dim[1])

Kent

PS to Liam: I suppose you could think of the above as a Schwartzian Transform :-)