[Tutor] Handling binary file

[Alan Gauld]

> I have opened a file in binary mode.
> The 9th, 10th and 11th bytes contain the time in seconds.
> In order to get this value in decimal I did the following:
>
> timeinsec = bytes[9] * 65536 + bytes[10] * 256 + bytes{11]
>
> Would someone please advise if there is a better way to do 
> this?

You could use:

timeinsec = bytes[9:12]

which gets you the three bytes as a sequence.

You should be able to use the struct module to convert that into
a number except that struct expects an integer to be 4 bytes so
you probably need to add a zero in front. It also depends on
issues like big-endian v little endian (ie right or left hand 
alignment)
etc.

If your method works I wouldn't worry too much!

Alan G