[Tutor] Printing columns of data

[Bob Gailer]

At 01:03 PM 2/8/2005, Kooser, Ara S wrote:
>Content-class: urn:content-classes:message
>Content-Type: multipart/alternative;
>         boundary="----_=_NextPart_001_01C50E19.4E45912A"
>
>Hello all,
>
>    I am writing a program to take a data file, divide it up into columns 
> and print the information back with headers. The data files looks like this
>
>       0.0 -3093.44908 -3084.59762   387.64329    26.38518  0.3902434E+00 
> -0.6024320E-04  0.4529416E-05
>       1.0 -3094.09209 -3084.52987   391.42288   105.55994  0.3889897E+00 
> -0.2290866E-03  0.4187074E-03
>       2.0 -3094.59358 -3084.88826   373.64911   173.44885  0.3862430E+00 
> -0.4953443E-03  0.2383621E-02
>         etc

>         10.0 ...
>
>So I wrote the program included below and it only prints the last line of 
>the file.
>
>Timestep    PE
>10.0      -3091.80609
>
>I have one question. Do I need to put ts and pe into a list before I print 
>then to screen or I am just missing something. Thanks.
>
>Ara
>
>import string
>
>inp = open("fort.44","r")
>all_file = inp.readlines()
>inp.close()
>
>outp = open("out.txt","w")
>
>cols = map(string.split,all_file)
>##print cols
>
>Data = {}
>for line in cols:
>     ts = line[0]
>#    print line[0]
>     pe = line[1]
>#    print line[1]
>
>print """
>
>Timestep    PE"""
>print "%s      %s     " % (ts,pe)
>
>outp.close()

Put the print statement in the for loop.
for line in cols:
     ...
     print "%s      %s     " % (ts,pe)

Bob Gailer
mailto:bgailer at alum.rpi.edu
303 442 2625 home
720 938 2625 cell 
-------------- next part --------------
An HTML attachment was scrubbed...
URL: http://mail.python.org/pipermail/tutor/attachments/20050208/03a98ee6/attachment.htm