[Tutor] count words

[Ron Nixon]

Thanks to everyone who replied to my post. All of your
suggestions seem to work. My thanks

Ron


--- Ryan Davis <ryan at acceleration.net> wrote:

> You could use split() to split the contents of the
> file into a list of strings.
> 
> ###
> >>> x = 'asdf foo bar foo'
> >>> x.split()
> ['asdf', 'foo', 'bar', 'foo']
> ###
> 
> Here's one way to iterate over that to get the
> counts.  I'm sure there are dozens.
> ###
> >>> x = 'asdf foo bar foo'
> >>> counts = {}
> >>> for word in x.split():
> ...	counts[word] = x.count(word)
> ... 
> >>> counts
> {'foo': 2, 'bar': 1, 'asdf': 1}
> ###
> The dictionary takes care of duplicates.  If you are
> using a really big file, it might pay to eliminate
> duplicates from the list
> before running x.count(word)
> 
> Thanks,
> Ryan 
> 
> -----Original Message-----
> From: tutor-bounces at python.org
> [mailto:tutor-bounces at python.org] On Behalf Of Ron
> Nixon
> Sent: Tuesday, February 15, 2005 11:22 AM
> To: tutor at python.org
> Subject: [Tutor] count words
> 
> 
> I know that you can do this to get a count of home
> many times a word appears in a file
> 
> 
> f = open('text.txt').read()
> print f.count('word')
> 
> Other than using a several print statments to look
> for
> seperate words like this, is there a way to do it so
> that I get a individual count of each word:
> 
> word1 xxx
> word2 xxx
> words xxx
> 
> etc.
> 
> 
> 
> 
> 		
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