[Tutor] Queued threads

[Liam Clarke]

Oops, you probably want to do this then- 

for i in range( 0, 3 ):
     oThread = Thread( target=mainFunction ).start()

    while oThread: 
             print 'sleeping 3 seconds'
             time.sleep( 3 )

A if <condition> generally has an implicit else: pass clause as I
think of it, so it will just keep reiterating if the condition isn't
met.

To see what I mean try - 

for i in range(5):   
   #The 0 is default starting for range function
   if i==15:
     print 'fifteen'
   print i 

You'll, of course, get 

0
1
2
3
4

It won't wait until i equals 15. 

on the other hand - 

for i in range(5): 
   
     while i != 15:
           print "nope"
     print i 


You'll get a runaway while, and 'nope' will cascade down your stream,
and you'll have great trouble closing Python. But i will never get
printed, as it will still be waiting for i to equal fifteen.


On Tue, 15 Feb 2005 21:54:04 -0500, Bernard Lebel
<python at bernardlebel.com> wrote:
> That is an attempt to catch the death of the thread. I guess I'm not
> taking the right steps ;-)
> 
> 
> Bernard
> 
> 
> Liam Clarke wrote:
> > I'm sorry, but when does oThread get the value 1?
> >
> > If you're testing for it's existence via a True/False thing, try
> >
> > if oThread:
> >
> > But otherwise, I'm not sure what you're expecting to get.
> >
> >
> > On Tue, 15 Feb 2005 20:58:15 -0500, Bernard Lebel
> > <python at bernardlebel.com> wrote:
> >
> >>Hello,
> >>
> >>I have already messed a little with simple thread programming, wich took
> >>this form:
> >>
> >>from threading import Thread
> >>
> >>def mainFunction():
> >>        pass
> >>
> >>Thread( target=mainFunction ).start()
> >>
> >>Now, I have a list of "jobs", each job being a windows bat file that
> >>launches an executable and performs a rendering task. So I have this
> >>queue of jobs, and would like to launch one only when the previous one
> >>has finished, and in a separate window. So far I have not been having
> >>much success with simple stuff:
> >>
> >>from threading import Thread
> >>
> >>def mainFunction():
> >>     print 'function print'
> >>     return 1
> >>
> >>for i in range( 0, 3 ):
> >>     oThread = Thread( target=mainFunction ).start()
> >>
> >>     if oThread == 1:
> >>             print 'sleeping 3 seconds'
> >>             time.sleep( 3 )
> >>
> >>In this example, 'sleeping 3 seconds' not returned, and each thread is
> >>started without any waiting.
> >>
> >>I'm looking at the various threading module details in the library but I
> >>have to admit that, well, I'm a bit at loss here.
> >>
> >>Thanks in advance
> >>Bernard
> 
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> http://mail.python.org/mailman/listinfo/tutor
> 


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