[Tutor] RE:
Danny Yoo
dyoo at hkn.eecs.berkeley.edu
Tue Jan 18 08:17:34 CET 2005
> > >>> stuff = [[0,'sdfsd','wrtew'], [1, 'rht','erterg']]
> > >>> stuff
> > [[0, 'sdfsd', 'wrtew'], [1, 'rht', 'erterg']]
> > >>> print [stuff[i][0] for i in range(len(stuff))]
> > [0, 1]
> >
> > An alternative way to write this is:
> >
> > ###
> > print [row[0] for row in stuff]
> > ###
> >
> > which extracts the first element out of every "row" sublist in
> > 'stuff'.
> This is fine. I just want to know if row is a reserve word? or is it a
> built in function in IDLE environment. The word row is not highlighted.
> What data type is (row)?
Hello!
When we have 'stuff' like this:
###
>>> stuff = [[0,'sdfsd','wrtew'], [1, 'rht','erterg']]
###
then we can ask for an element out of 'stuff'. One thing we can do is
variable assignment:
###
>>> row = stuff[0]
###
'row' here is just an arbitrarily chosen variable name. We can see that
"row"'s value is one of the sublists in 'stuff' by trying:
###
>>> print row
[0, 'sdfsd', 'wrtew']
###
We can also use a 'for' loop to march --- to "iterate" --- across a list:
###
>>> for row in stuff:
... print row, "is another element in 'stuff'"
...
[0, 'sdfsd', 'wrtew'] is another element in 'stuff'
[1, 'rht', 'erterg'] is another element in 'stuff'
###
'row' here is also used as a temporary variable name. In a 'for' loop, it
is assigned to each element, as we repeat the loop's body.
If you have more questions, please feel free to ask.
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