[Tutor] finding path to resource files in a GUI

[Christian Meesters]

On 9 Jun 2005, at 12:00, Michael Lange wrote:

> Hi Christian,
>
> try
>
>     self.cwd = os.path.abspath(sys.path[0])
>
> sys.path[0] is the directory of your main program file, with 
> os.path.abspath() you can
> get rid of the "../../" stuff at the beginning of the path if the 
> program is called from a link.
>
> I hope this helps

It does! Actually I tried abspath, but didn't think of this very 
combination with sys.path ...

Thanks a lot!
Danke,
Christian