[Tutor] 2d list matrix 7 x 75 problem

[Max Noel]

On Mar 6, 2005, at 09:49, Dave S wrote:

> so I thought I would be clever with ...
> >>> a=[0]*5
> >>> a
> [0, 0, 0, 0, 0]
> >>> b=[a[:]]*5
>
> same problem.
>
> It seems realy simple but how do I generate a 7 x 75 list matrix ?
>
> Dave

	Try this:

 >>> a = [''] * 5
 >>> b = [a[:] for i in range(5)]
 >>> b
[['', '', '', '', ''], ['', '', '', '', ''], ['', '', '', '', ''], ['', 
'', '', '', ''], ['', '', '', '', '']]
 >>> b[0] is b[1]
False

	List comprehensions. Gotta love 'em... ^^

> Is there a more elegant solution to
>
> if string == 'sun' or string == 'mon' or string == 'tue' or string == 
> 'wed' or string == 'thu' or string == 'fri' or string == 'sat':

	Yes, there is.

if a in ('sun', 'mon', 'tue', 'wed', 'thu', 'fri', 'sat'):

(also works with a list or a dictionary)

-- Max
maxnoel_fr at yahoo dot fr -- ICQ #85274019
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