[Tutor] re.findall vs. re.search and re.match

[Ron Nixon]

Kent:

The code is below. Here's the error message. 

Traceback (most recent call last):
  File "C:/Python24/reformat.py", line 5, in
-toplevel-
    name = x.group(1)
AttributeError: 'list' object has no attribute 'group'




import re
f = open('reformat.txt').read()
pat = re.compile(r"([^\r\n]+)\n([^\r\n]*)\n([^\r\n]*)
([^\r\n]*) ([^\r\n]*)")
x=re.findall(pat,f)
name = x.group(1)
address = x.group(2)
citystate = x.group(3)+x.group(4)
zipcd = x.group(5)
o= open('reformat1.txt','w')
o.write("%s,%s,%s,%s\n" % (name, address,
citystate,zipcd))
o.close()
print("%s,%s,%s,%s\n" % (name, address,
citystate,zipcd))
--- Kent Johnson <kent37 at tds.net> wrote:
> Ron Nixon wrote:
> > Thanks to all who replied to my post earlier on
> re's.
> > I'm still preplexed by why re.search and re.match
> > works in the code below, but not re.findall.
> > re.findall is suppose to return all
> non-voerlapping
> > occurances of the  pattern that matches in this
> > example, but it returns errors. Looking through
> the
> > docs and from what I can see it should work. Can
> > anyone provide advice.
> 
> Please show the code that uses re.findall() and the
> error you receive when you run it.
> 
> Kent
> 
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> http://mail.python.org/mailman/listinfo/tutor
> 


		
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