[Tutor] primes
Pierre Barbier de Reuille
pierre.barbier at cirad.fr
Fri Mar 18 12:08:14 CET 2005
Gregor Lingl a écrit :
> Hi!
> Who knows a more concise or equally concise but more efficient
> expression, which returns the same result as
>
> [x for x in range(2,100) if not [y for y in range(2,x) if x%y==0]]
>
> Gregor
>
> P.S.: ... or a more beautiful one ;-)
>
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The fastest know way for your problem is the Eratosten sieve ...
Here's an implementation :
from sets import Set
from math import sqrt
def sieve( max ):
max_val = int( sqrt( max ) )
s = Set(xrange( 4, max, 2 ))
for i in xrange( 3, max_val, 2 ):
s.update( xrange( 2*i, max, i ) )
return [ i for i in xrange( 2, max ) if i not in s ]
I compared with the implementations of Gregor (optimized) and Max and
here is the result :
listPrimes(100000) = 0.637619972229 (Max implementation)
primeConciseOptimized(100000) = 2.9141831398 (Gregor optimized)
sieve(100000) = 0.49525809288 (Eratosten sieve)
You'll just notice that Eratosten sieve is O(n) space consumption when
others are less (I don't remember the density of prime numbers :o) )
were n is the maximum number you're looking for.
Pierre
--
Pierre Barbier de Reuille
INRA - UMR Cirad/Inra/Cnrs/Univ.MontpellierII AMAP
Botanique et Bio-informatique de l'Architecture des Plantes
TA40/PSII, Boulevard de la Lironde
34398 MONTPELLIER CEDEX 5, France
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