[Tutor] Why is this not an error?
Hameed U. Khan
hameed.u.khan at gmail.com
Sun Mar 20 15:20:37 CET 2005
On Sunday 20 Mar 2005 1846, Steve N wrote:
> This code runs, but it seems to me it should generate
> a syntax error. Can someone explain what's going on?
Why do you think there is a syntax error?
> x = [1,2,3,4]
> z = 4
> if z in x:
> print 'found:', z
if clause has been ended here.
> for i in x:
> print 'in the loop with', i
> else:
> print 'not found:', z
This else is the part of the for loop. And the statements in this else will be
executed if your for loop will complete all of its iterations. if you want
this else with 'if' statement then remove the for loop.
>
> found: 4
> in the loop with 1
> in the loop with 2
> in the loop with 3
> in the loop with 4
> not found: 4
>
> --
> Steve
>
>
>
>
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--
Hameed U. Khan, <hameed.u.khan at gmail dot com>
Registered Linux User #: 354374
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