[Tutor] how to read from a txt file

[jrlen balane]

am getting desperate on this, please help me, I just can't figure out
how to read those tabs

please help me!


On Tue, 29 Mar 2005 22:16:11 -0800, jrlen balane <nbbalane at gmail.com> wrote:
> I need the string representation of the data read so that i can put it
> on a wxGrid
> while i am goin to need the integer representation of the data so that
> i can plot it.
> 
> anybody, please help!!!
> 
> 
> On Tue, 29 Mar 2005 20:56:16 -0800, jrlen balane <nbbalane at gmail.com> wrote:
> > how should i modify this data reader:
> > (assumes that there is only one entry per line followed by '\n')
> >
> > data_file = open(os.path.normpath(self.TextFile.GetValue()), 'r')
> > data = data_file.readlines()
> >
> > self.irradianceStrings = map(str, data)
> > self.irradianceIntegers = map(int, data)
> > self.IrradianceExecute.SetValue(''.join(self.irradianceStrings))
> >
> > so that i can read the text file created by this:
> >
> > self.filename = "%s\%s.txt"
> > %(os.path.normpath(self.SaveFolder.GetValue()),time.strftime("%Y%m%d%H%M"))
> >
> > self.table_file = open(self.filename,"a")
> > self.table_file.write('%f\t'%self.temp11)
> > self.table_file.write('%f\t'%self.temp22)
> > self.table_file.write('%f\t'%self.pyra11)
> > self.table_file.write('%f\t'%self.pyra22)
> > self.table_file.write('%f\t'%self.voltage11)
> > self.table_file.write('%f\t'%self.current11)
> > self.table_file.write('\n')
> > self.table_file.close()
> >
> >
> > On Tue, 15 Mar 2005 17:05:46 +1300, Liam Clarke <cyresse at gmail.com> wrote:
> > > Whoops, golden rule - "Never post untested code"
> > > Sorry.
> > >
> > >
> > > On Mon, 14 Mar 2005 21:05:44 -0500, Kent Johnson <kent37 at tds.net> wrote:
> > > > jrlen balane wrote:
> > > > > ok, i've done what sir Kent just said, my fault...
> > > > >
> > > > > but an error still occurs:
> > > > > Traceback (most recent call last):
> > > > >   File "C:\Python23\practices\opentxtprintlngnew.py", line 18, in -toplevel-
> > > > >     print process(data)
> > > > >   File "C:\Python23\practices\opentxtprintlngnew.py", line 10, in process
> > > > >     tempLine = int(line)
> > > > > ValueError: invalid literal for int(): abc
> > > > >
> > > > > isn't this the job of :
> > > > >
> > > > > except TypeError:
> > > > >             print "Non numeric character in line", line
> > > > >             continue #Breaks, and starts with next line
> > > >
> > > > Yes, only it should be ValueError instead of TypeError. You can check this interactively:
> > > >   >>> int('foo')
> > > > Traceback (most recent call last):
> > > >    File "<stdin>", line 1, in ?
> > > > ValueError: invalid literal for int(): foo
> > > >
> > > > Kent
> > > >
> > > > _______________________________________________
> > > > Tutor maillist  -  Tutor at python.org
> > > > http://mail.python.org/mailman/listinfo/tutor
> > > >
> > >
> > > --
> > > 'There is only one basic human right, and that is to do as you damn well please.
> > > And with it comes the only basic human duty, to take the consequences.
> > > _______________________________________________
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> > > http://mail.python.org/mailman/listinfo/tutor
> > >
> >
>