[Tutor] python problem

[Andrei]

Feziwe Mpondo <feziwe <at> sanbi.ac.za> writes:

> i'm trying to write a code that handle errors help

I think the indentation was screwed up.

> while menu_choice != 5:
>     menu_choice = input("Type in a number (1-5):")

I'd avoid using input. Use raw_input instead.

>     break

break stops a loop. So you display the menu once and stop immediately after the
user has selected an action. That can't be right.

>         except(TypeError,NameError):

Exceptions are caught in a try except block, where the code that might
malfunction comes after try, and the code to handle the malfunctioning comes
after except. It therefore looks something like this:

  userinput = raw_input('Choice: ')
  try: # userinput may or may not be valid
      choice = int(userinput) # might fail if userinput is random text
  except (ValueError): # what to do if couldn't convert to integer
      print 'Not a number'
      choice = 5

Yours,

Andrei