[Tutor] Aschenputtel problem

[Kent Johnson]

Alan Gauld wrote:
>>I wonder if there is a shorter form of the following idiom:
> 
> 
> Bearing in mind that shorter is not necessarily better...
> 
> [condition(i) and list1.append(i) or list2.append(i) for i in 
> original]

Hmm, no, this will always evaluate list2.append(i) because the value of list1.append(i) is None. You could use

[ (condition(i) and list1 or list2).append(i) for i in original ]

or

for i in original:
  (condition(i) and list1 or list2).append(i)

Kent