[Tutor] Question on regular expressions

[Andrew Robert]

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Great!

Taking this a little further along, I wrote the converted file to a new
file using:


import re,sys

output = open(r'e:\pycode\out_test.txt','wb')

for line in open(r'e:\pycode\sigh.txt','rb') :
    output.write( re.sub(r'([^\w\s])', lambda s: '%%%2X' %
ord(s.group()), line))

output.close()


Not elegant but its strictly for test :)


Last part and we can call it a day.

How would you modify the lambda statement to covert a the hex value back
to its original value?


Do I need to incorporate base64.16basedecode somehow?

The original perl code to covert back to normal is:

	`perl -ple 's/(?:%([0-9A-F]{2}))/chr hex $1/eg' somefiletxt



Kent Johnson wrote:
> Yes, this is a feature of print, it always inserts a newline. To avoid 
> this, use sys.stdout.write() instead of print:
> for line i open(r'e:\pycode\sigh.txt','rb'):
>      line = re.sub(r'([^\w\s])', lambda s: '%%%2X' % ord(s.group()), line)
>      sys.stdout.write(line)
> 
> Kent
> 
<snip>

</snip>

- --
Thank you,
Andrew Robert
Systems Architect
Information Technologies
MFS Investment Management
Phone:   617-954-5882

E-mail:  arobert at mfs.com
Linux User Number: #201204
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