[Tutor] sorting lists in dictionary values
Eric Abrahamsen
eric at abrahamsen.com
Sun Aug 26 11:43:32 CEST 2007
> From noob to noob : sort sorts in place. I seem to remember it
> returns nothing.
>
> This works:
>
> In [12]: directoryOut[12]:
> {'A': ['Abercrombie', 'Aalberg'],
> 'B': ['Barnaby', 'Black', 'Biggles'],
> 'D': ['Douglas', 'Dawn', 'Diggle'],
> 'G': ['Granger', 'Gossen']}
>
> In [13]: for key in directory:
> directory[key].sort()
>
> In [14]: directory
> Out[14]:
> {'A': ['Aalberg', 'Abercrombie'],
> 'B': ['Barnaby', 'Biggles', 'Black'],
> 'D': ['Dawn', 'Diggle', 'Douglas'],
> 'G': ['Gossen', 'Granger']}
>
> Please let me know if I'm wrong!
>
> Best
>
> Chris
Beautiful, that works perfectly. A single line added to the list
comprehension:
for item in letters:
phonebook[item] = [name for name in names if name.startswith(item)]
phonebook[item].sort()
and all is well.
Thanks for the help,
Eric
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