[Tutor] creating the equivalent of string.strip()

[Andrew James]

*headbang*

I'm an idiot. s=s[:-2] should be s=s[:-1].

Andrew James wrote:
> And as soon as I send it again I realise a pretty stupid error. The 
> two loops shouldn't be nested.
>
> Andrew James wrote:
>> Helps if I send it to the group...
>>
>> And Kent, I didn't post it originally because I figured the other guy 
>> was still working on his script. Besides, I didn't think it'd be that 
>> far fetched for you to assume I was using something like "while s[0] 
>> == ' ':"
>>
>> Andrew James wrote:
>>> I'm always nervous about sharing my code... It's like being back in 
>>> high school, I don't want the other kids to laugh at me. Anyway, 
>>> running that in IDLE with a string such as '                      
>>> testing.          ' Will print '                    testing' at the 
>>> end of the first (second, really) loop.
>>>
>>> def strip(s):
>>>    while s[0].isspace() == True:
>>>        while s[-1].isspace() == True:
>>>            s = s[:-2]
>>>            print s
>>>        s = s[1:]
>>>        print s
>>>
>>> test = raw_input('Enter a string with plenty of leading and trailing 
>>> whitespace:')
>>>
>>> strip(test)
>>>
>>> Alan Gauld wrote:
>>>> "Andrew James" <aijames at exemail.com.au> wrote
>>>>
>>>>  
>>>>> string containing a single space ' ' but even using s[-1].isspace() I
>>>>> lose punctuation marks. Any idea why that's happening?
>>>>>     
>>>>
>>>> care to show us what you are doing?
>>>>
>>>>  
>>>>>>> ';'.isspace()
>>>>>>>         
>>>> False
>>>>
>>>> So puntuation should not show up as true...
>>>>
>>>> Alan G.
>>>>
>>>>
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>>>>
>>>>
>>>>   
>>>
>>
>