[Tutor] Update values stored as a list in a dictionary with values from another dictionary

[GTXY20]

I seem to be encountering a problem and I think it is because I actually
have my data as follows:

data = {1:[a,b,c], 2:[a,c], 3:[b,c], 4:[a,d]}

not as previously mentioned:

data = {1:(a,b,c), 2:(a,c), 3:(b,c), 4:(a,d)}

So the values are actually stored as a list.

I am trying to adjust so that data ends up being:

{1:[1,2,3], 2:[1,3], 3:[2,3], 4:[1,d]}

right now I am getting:

{1:[[1],[2],[3]], 2:[[1],[3]], 3:[[2],[3]], 4:[[1],d]}

which is problmatic for other things I am trying to do - it is indicating
that the values are not hashable.





On 10/2/07, John Fouhy <john at fouhy.net> wrote:
>
> On 02/10/2007, GTXY20 <gtxy20 at gmail.com> wrote:
> > Hello all,
> >
> > Let's say I have the following dictionary:
> >
> > {1:(a,b,c), 2:(a,c), 3:(b,c), 4:(a,d)}
> >
> > I also have another dictionary for new value association:
> >
> > {a:1, b:2, c:3}
> >
> > How should I approach if I want to modify the first dictionary to read:
> >
> >  {1:(1,2,3), 2:(1,3), 3:(2,3), 4:(1,d)}
> >
> > There is the potential to have a value in the first dictionary that will
> not
> > have an update key in the second dictionary hence in the above
> dictionary
> > for key=4 I still have d listed as a value.
>
> You could use the map function...
>
> Let's say we have something like:
>
> transDict = { 'a':1, 'b':2, 'c':3 }
>
> We could define a function that mirrors this:
>
> def transFn(c):
>     try:
>         return transDict[c]
>     except KeyError:
>         return c
>
> Then if you have your data:
>
> data = { 1:('a','b','c'), 2:('a','c'), 3:('b','c'), 4:('a','d')}
>
> You can translate it as:
>
> for key in data.keys():
>     data[key] = map(transFn, data[key])
>
> HTH!
>
> --
> John.
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: http://mail.python.org/pipermail/tutor/attachments/20071002/a54c9e21/attachment.htm