[Tutor] Update values stored as a list in a dictionary with values from another dictionary

[GTXY20]

Sorry - solved my own problem - it was the way I was creating my dictionary
and assigning the value as a list.

I will post my final working code shortly.

M.

On 10/2/07, GTXY20 <gtxy20 at gmail.com> wrote:
>
> I seem to be encountering a problem and I think it is because I actually
> have my data as follows:
>
> data = {1:[a,b,c], 2:[a,c], 3:[b,c], 4:[a,d]}
>
> not as previously mentioned:
>
> data = {1:(a,b,c), 2:(a,c), 3:(b,c), 4:(a,d)}
>
> So the values are actually stored as a list.
>
> I am trying to adjust so that data ends up being:
>
> {1:[1,2,3], 2:[1,3], 3:[2,3], 4:[1,d]}
>
> right now I am getting:
>
> {1:[[1],[2],[3]], 2:[[1],[3]], 3:[[2],[3]], 4:[[1],d]}
>
> which is problmatic for other things I am trying to do - it is indicating
> that the values are not hashable.
>
>
>
>
>
> On 10/2/07, John Fouhy <john at fouhy.net> wrote:
> >
> > On 02/10/2007, GTXY20 < gtxy20 at gmail.com> wrote:
> > > Hello all,
> > >
> > > Let's say I have the following dictionary:
> > >
> > > {1:(a,b,c), 2:(a,c), 3:(b,c), 4:(a,d)}
> > >
> > > I also have another dictionary for new value association:
> > >
> > > {a:1, b:2, c:3}
> > >
> > > How should I approach if I want to modify the first dictionary to
> > read:
> > >
> > >  {1:(1,2,3), 2:(1,3), 3:(2,3), 4:(1,d)}
> > >
> > > There is the potential to have a value in the first dictionary that
> > will not
> > > have an update key in the second dictionary hence in the above
> > dictionary
> > > for key=4 I still have d listed as a value.
> >
> > You could use the map function...
> >
> > Let's say we have something like:
> >
> > transDict = { 'a':1, 'b':2, 'c':3 }
> >
> > We could define a function that mirrors this:
> >
> > def transFn(c):
> >     try:
> >         return transDict[c]
> >     except KeyError:
> >         return c
> >
> > Then if you have your data:
> >
> > data = { 1:('a','b','c'), 2:('a','c'), 3:('b','c'), 4:('a','d')}
> >
> > You can translate it as:
> >
> > for key in data.keys():
> >     data[key] = map(transFn, data[key])
> >
> > HTH!
> >
> > --
> > John.
> >
>
>
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