[Tutor] Creating Sudoku

[Luke Paireepinart]

W W wrote:
> On 4/7/08, Luke Paireepinart <rabidpoobear at gmail.com> wrote:
>   
>> W W wrote:
>>  What are you talking about?  I don't understand what you mean by "ignores
>> whitespace between dictionary elements."
>>
>>     
>>> foo = {'1a': 1, '1b':2, '1c':3,
>>>           '2a': 0, '2b': 9, '2c': 6}
>>>       
>
> Exactly that. If you were to write:
>
> foo = {'1a': 1, '1b':2, '1c':3}
>     foo['2a'] = 0
>
> You would get a nifty error.
>   
You mean that the dictionary _definition_ ignores whitespace between 
elements?
That's quite different than the dictionary itself ignoring whitespace.  
That implies that
foo['1b'] is the same element as foo['1 b'], hence the source of  my 
confusion.

That's not a feature of dictionaries, but of the comma.
You can easily do the following:
x = [1, 2,
       3, 4]
if you want.
Same with tuples and various other things.
Python just realizes that if it doesn't see a closing brace/bracket, but 
sees a comma, that more will probably be coming on the next line.
You can do the same thing with backslash, if your statement does not end 
in a comma: for example,
x = 1 + 1 + \
      2 + 3 + 5 \
      + 8 + 13

Also, did you test the code that "generates an error?"
It works fine for me.
 >>> foo = {'1a': 'b'}
 >>> foo['2b'] = 0
 >>> print foo['2b']
0
 >>>

Hope that helps,
-Luke