[Tutor] cut all decimal places with zeros

[Tim Michelsen]

Hello,
how can I suppress the decimal places for (only those) numbers whos 
decimal places are zero (0)?

Example:

#### CODE ####
In [1]: m = 2.0

In [2]: n = 2.56789080

In [3]: n_format =  '%.4f' %n

In [4]: n_format
Out[4]: '2.5679'

In [5]: m_format =  '%.4f' %m

In [6]: m_format
Out[6]: '2.0000'

### END ####

I would like to have the "m_format" to be formatted like "2" and the 
n_format like "2.5679". How can I achive this?
A g with "2.4" should return "2.4" and not "2.4000".

Basically, I am looking for a way to eliminate the decimal places that 
are zero (0).

I tried this humble function before appling the formatting and it works 
well with the numbers:

### CODE ###
def cut_decimals(float):
	"""
	input: floating number
	output: number as string with zero decimals removed
	"""
	#print float-int(float)
	#print '%.4f' %float
	if float-int(float) != 0:
		number =  '%.4f' %float
		number = number.replace('0.','X.')
		number = number.replace('0','')
		number = number.replace('X.','0.')
	else:
		number =  '%.0f' %float
	return number

n = 2.0
m = 2.5678908
g = 2.4
h = 1.45
i = 0.67
numbers = [n, m, g, h, i]
for i in numbers:
	i_f = cut_decimals(i)
	print i_f

### END ###
### OUTPUT ###


  %run ./test_number.py
2
2.5679
2.4
1.45
0.67
### END ###

Is there any more efficient solution using string formatting only?

Thanks in adavance.

Kind regards,
Timmie