[Tutor] Nested dictionary with defaultdict

[GTXY20]

Thanks John and Kent for the guidance.

This following ends up working perfect for me - instead of print to the
console I will just write this to a text file. I will also wrap it in a
function.
from collections import defaultdict
d = {'1': ['220', '220', '220''], '2': ['220', '238', '238', '238', '238'],
'3': ['220', '238'], '4': ['220', '220'], '5': ['220', '220', '238'], '6':
['238', '238'], '7': ['220']}

for f, b in d.items():
    h = defaultdict(int)
    for j in b:
        h[j]+=1
    for k,v in sorted (h.items()):
        print ('%s, (%s:%s)' % (f, k, v))

M.


On Tue, Apr 15, 2008 at 10:19 PM, John Fouhy <john at fouhy.net> wrote:

> On 16/04/2008, GTXY20 <gtxy20 at gmail.com> wrote:
> > I currently have a dictionary like the following:
> >
> > {'1': ['220', '220', '220''], '2': ['220', '238', '238', '238', '238'],
> '3':
> > ['220', '238'], '4': ['220', '220'], '5': ['220', '220', '238'], '6':
> > ['238', '238'], '7': ['220']}
> >
> > I am trying to create a dictionary that would list the current key and a
> > count of the iterations of values within the value list like so:
> >
> > {'1': {'220' : 3}, '2': {'220' : 1}, 2: {238 : 4}, '3': {'220' : 1}, 3:
> {
> > '238' : 1}, '4': {220 : 2}, '5': {'220: 2}, '5': {238 : 1}, '6': {'238'
> :
> > 2}, '7': {'220' : 1}}
> [...]
> > I am looking for a satrting point or any suggestions.
>
> Can you write a function that will take a list and return a dictionary
> with the counts of elements in the list?
>
> i.e. something like:
>
> >>> def countValues(valueList):
> ...  # your code goes here
> ...
> >>> countValues(['220', '238', '238', '238', '238'])
> {'238': 4, '220': 1}
>
> P.S.  Your sample output is not a valid dictionary...
>
> --
> John.
>
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