[Tutor] String made of list elements' nth characters?

[R. Alan Monroe]

> Given a list of 6-letter words:
> ['abject','poetry','keypad']

> How do I derive this list:
> ['apk', 'boe', 'jey']

> (The original list's first letters, second letters, third letters,
> etc.)

> I have a text file of 15280 six-letter words and I want to robotically
> generate 6x6 word squares.

> My first attempt returns the right results, but _not in string form_.
> There's bound to be a really simple approach that I'm just not
> remembering.



Per usual, I figured out a working approach right after posting. Could
probably be optimized, but it works:

def checksolution(sol):
    maybes = []
    big = ''.join(solution)
    for x in range(len(sol)):
        maybes.append( big[x::6] )
    print maybes

solution=['abject','poetry','keypad']
checksolution(solution)

['apk', 'boe', 'jey']


Alan