[Tutor] replacing CreateProcess command for Vista compatibility?

Kirk Vander Meulen kvander11 at gmail.com
Thu Jan 10 19:25:27 CET 2008


Hi, I'm running the program Pymol (written in python) on Windows Vista, and
in trying to run one of its plugins, I em encountering the following error:

Error: 3
WindowsError Exception in Tk callback
  Function: <function <lambda> at 0x027C6DF0> (type: <type 'function'>)
  Args: ()
Traceback (innermost last):
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\Pmw\Pmw_1_2\lib\PmwBase.py", line 1747,
in __call__
    return apply(self.func, args)
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\Pmw\Pmw_1_2\lib\PmwDialog.py", line
153, in <lambda>
    command=lambda self=self, name=name: self._doCommand(name))
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\Pmw\Pmw_1_2\lib\PmwDialog.py", line
132, in _doCommand
    return command(name)
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\pmg_tk\startup\apbs_tools.py", line
1136, in execute
    good = self.generatePdb2pqrPqrFile()
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\pmg_tk\startup\apbs_tools.py", line
1683, in generatePdb2pqrPqrFile
    (retval,progout) = run(self.pdb2pqr.getvalue(),args)
  File "C:\Program
Files\DeLanoScientific\PyMOL/modules\pmg_tk\startup\apbs_tools.py", line
362, in run
    retcode = subprocess.call(args,stdout=output_file.fileno(),stderr=
subprocess.STDOUT)
  File "C:\Program Files\DeLanoScientific\PyMOL\py24\lib\subprocess.py",
line 413, in call
    return Popen(*args, **kwargs).wait()
  File "C:\Program Files\DeLanoScientific\PyMOL\py24\lib\subprocess.py",
line 543, in __init__
    errread, errwrite)
  File "C:\Program Files\DeLanoScientific\PyMOL\py24\lib\subprocess.py",
line 706, in _execute_child
    startupinfo)
WindowsError: [Errno 193] %1 is not a valid Win32 application


Probably not all of that is relevant, but I thought I'd at least lay it out
there in case there's something obvious there.  In doing crazy amounts of
googling, I *think* the problem is that the python file uses a command
called "createprocess()", and, while this may work ok in XP, it does not in
Vista (something to do with how the security setup has changed).  The
software is not guaranteed fully Vista-proof, so it seems like a possible
explantion.

So I'm hoping, although not very optimistically, that I can tweak this
command and regain compatibility with Vista.  One site I found suggests
using either "ShellExecute()" or "ShellExecuteEx()" in lieu of
"createprocess()".  Would this be a simple fix- how much would I have to
change?  Here is the relevant call:

                hp, ht, pid, tid = CreateProcess(executable, args,
                                         # no special security
                                         None, None,
                                         # must inherit handles to pass std
                                         # handles
                                         1,
                                         creationflags,
                                         env,
                                         cwd,
                                         startupinfo)

Thanks for any help,

Kirk
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