[Tutor] basic lists and loops question
Kent Johnson
kent37 at tds.net
Wed May 14 23:31:04 CEST 2008
On Wed, May 14, 2008 at 3:02 PM, Jon Crump <jjcrump at myuw.net> wrote:
> Something basic about lists and loops that I'm not getting here.
> I have a function that searches through them to find pairs of dictionaries
> that satisfy certain criteria. When the nested loops find such a pair, I
> need to merge them. So far so good. This works:
>
> def events(data):
> evts = []
> for x in lst:
> for y in lst:
> if (x['placename'] == y['placename']) and (x['end'].month + 1 ==
> y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)):
> evts.append({'placename': x['placename'], 'long-name':
> x['long-name'], 'start': x['start'], 'end': y['end']})
> evts.append(x)
> return evts
>
> for x in events(lst):
> print x
>
> But then I need to delete the two original dictionaries that I merged. If I
> do del x, I get an error "local variable 'x' referenced before assignment"
Not sure why you got that error but it general it is not a good idea
to delete items from a container you are iterating; the results can be
unpredictable.
>
> I've also tried decorating the processed dictionaries in the if loop thus:
> x['processed'] = True
> y['processed'] = True
>
> Then when I call events() I get back the merged dict and the decorated
> dicts:
>
> {'placename': u'Lincoln, Lincolnshire', 'end': datetime.date(1216, 10, 2),
> 'start': datetime.date(1216, 9, 28), 'long-name': u'Lincoln, Lincolnshire.'}
> {'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
> datetime.date(1216, 9, 30), 'start': datetime.date(1216, 9, 28),
> 'long-name': u'Lincoln, Lincolnshire.'}
> {'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
> datetime.date(1216, 10, 2), 'start': datetime.date(1216, 10, 1),
> 'long-name': u'Lincoln, Lincolnshire.'}
>
> But if I try to call events() thus:
>
> for x in events(lst):
> if x['processed'] == True:
> print x
>
> I get a KeyError.
The problem is that not every dict has the 'processed' key. Try
if x.get('processed') == True:
or just
if x.get('processed'):
x.get() will return None (instead of raising KeyError) if the key is
not present.
Kent
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