[Tutor] Open a directory in the default file manager
Tim Michelsen
timmichelsen at gmx-topmail.de
Mon May 19 21:36:30 CEST 2008
Hi!
> > is there any function/module that allows me to open a directory in the
> > default file manager of a operating system?
>
> On Windows you can use os.startfile().
> On "pure" Unices there's no such thing as filetype associations
> However, if you use a desktop environment, you can spawn xdg-open (from
> xdg-utils) from Python. This will autodetect gnome, kde and xfce and use
> their tools (gnome-open, kfmclient, exo-open).
> I think on OS X/Darwin there's a similar utility called `open'.
>
> You can use sys.platform to determine which system you're running on.
I wasn't able to start explorer with os.startfile()
I then used
subprocess.call(['explorer', my_directory])
And it works.
Kind regards,
Timmie
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