[Tutor] get a module's own (top_level) dict?

[Emile van Sebille]

spir wrote:
> Hello pyhonistas,
> 
> Example:
> === module content ===
> a = 1
> b = 2
> ======================
> 
> I'm looking for a way to get something like {'a':a, b':2}. 

Maybe this will get you started:

[root at vsds2 root]# cat > testmod.py
a=1
b=2
[root at vsds2 root]# python
Python 2.5 (r25:51908, Nov  1 2006, 15:36:22)
[GCC 2.96 20000731 (Red Hat Linux 7.1 2.96-98)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
 >>> import testmod
 >>> dir(testmod)
['__builtins__', '__doc__', '__file__', '__name__', 'a', 'b']
 >>> D=dict([(varname,getattr(testmod,varname))
         for varname in dir(testmod)
         if not varname.startswith("_") ])
 >>> D
{'a': 1, 'b': 2}
 >>>

HTH,

Emile


> Actually, 
> names defind in the module will be instances of a custom type. I want to 
> give them an attribute that holds their own name. E.g.:
> for key,obj in dict:
>     obj.name = key
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