[Tutor] Reading from files problem

[Chris Castillo]

this worked for me fine.

#Author - Chris Castillo
#Created 4/19/09
#Program 6

import time

#Open and read text file with student information
gradesfile = open("grades.dat", "r")
time_acc = time.asctime()

#Ask user for student ID to lookup student information
sought_id = raw_input("Please enter a student identifier to look up grades:
")



#Assign values for each students' info in list
for line in gradesfile:
    lines = line.split(",")
    student_id = lines[0]
    last_name = lines[1]
    first_name = lines[2]
    major = lines[3]
    hw1 = lines[4]
    hw2 = lines[5]
    hw3 = lines[6]
    hw4 = lines[7]
    hw5 = lines[8]
    hw6 = lines[9]
    hw7 = lines[10]
    test1 = lines[11]
    test2 = lines[12]
    test3 = lines[13]

    #Arithmetic operations for all students' grades
    total_points = 550
    hw_grades = float(hw1) + float(hw2) + float(hw3) + float(hw4) +
float(hw5) + float(hw6) + float(hw7)
    test_grades = float(test1) + float(test2) + float(test3)
    student_points = float(hw_grades) + float(test_grades)
    avg_grade = round(float(student_points / total_points) * 100.0, 2)

    #Assign grades to letter values
    if avg_grade < 60:
         letter_grade="F"
    elif avg_grade < 70:
         letter_grade="D"
    elif avg_grade < 80:
         letter_grade="C"
    elif avg_grade < 90:
         letter_grade="B"
    elif avg_grade < 101:
         letter_grade="A"
    else:
         print avg_grade, "is not valid"

    #variable for output to request.dat text file
    req_output = student_id + ", " + last_name + ", " + first_name + ", " +
time_acc

    #Check to see if student id number is in the list of student id numbers
    if lines[0] == sought_id:

        new_file = open("requests.dat", "w+")
        new_file.write(req_output)


        print "\n", last_name + ", "+ first_name + ", " + student_id + ", "
+ major
        print "\n", time_acc
        print "\nExams - ", test1 + ", " + test2 + ", " + test3
        print "Homework - ", hw1, ", ",hw2, ", ", hw3, ", ", hw4, ",", hw5,
", ", hw6, ", ", hw7
        print "\nTotal points earned - ", student_points
        print "\nGrade:  ", avg_grade, "that is a ", letter_grade

gradesfile.close()

hope this helps someone. I know it's probably not the most efficient way to
handle this kind of problem but It works nonetheless.






On Mon, Apr 20, 2009 at 8:24 AM, Alan Gauld <alan.gauld at btinternet.com>wrote:

>
> "Scott SA" <pydev at rscorp.ab.ca> wrote
>
>  May have been a bad assumption on my part as I envisioned pickling a
>>  dict. and that just got too complicated.
>>
>
> A pickled dict?
> That would be a shelve mebbe?
>
>
>  PS. My email is acting up, did my prev. message actually make it to  the
>> list?
>>
>
> Yes, I saw it just after sending mine...
>
> Alan G
>
>
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> http://mail.python.org/mailman/listinfo/tutor
>
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