[Tutor] transforming an integer to a list of integers

[Andre Engels]

On Tue, Feb 3, 2009 at 4:17 PM, H.G. le Roy <hgleroy at gmail.com> wrote:
> Hi,
>
> recently I learned about Project Euler (http://projecteuler.net/) and now
> I'm trying to work me through. At the moment I'm thinking about
> http://projecteuler.net/index.php?section=problems&id=8
>
> One step for my solution should be transforming this big integer to a list
> of integers. I did:
>
> import math
>
> bignr = 12345
> bignrs =[]
>
> for i in xrange(math.ceil(math.log10(bignr)):
>   rem = bignr % 10
>   bignrs.append(rem)
>   bignr /= 10
>
> However this "feels" a bit complicated, Do you know a better (more simple,
> nice etc.) way to do this?

One way could be to represent the number as a string; a string can be
treated as a list, so you get what you want quite quickly that way:

bignr = 12345
bignrs =[]

for char in str(bignr):
    bignrs.append(int(char))




-- 
André Engels, andreengels at gmail.com