[Tutor] Better way - fnmatch with list ? CORRECTION

[bob gailer]

bob gailer wrote:
> Damon Timm wrote:
>> Hi - am learning Pythong and loving it!   Anyhow, what I have works,
>> but I wondered if there was a "better" (more python-y) way.
>>
>> Here is what I am doing with fnmatch ... am thinking there has to be a
>> one-line way to do this with a lambda or list comprehension ... but my
>> mind can't get around it ... I have other code, but the main part is
>> that I have a list of files that I am going through to check if they
>> have a given extension ... in this part, if the file matches any of
>> the extension I am looking for, I want it to do some stuff ... later I
>> check it against some other extensions to do "other" stuff:
>>
>> for file in files:
>>     for ext in ['*.flac','*.mp3','*.m4a']:
>>         if fnmatch.fnmatch(someFile, ext):
>>             #do some stuff if the someFile matches one of the items 
>> in the list
>>   
>
> Since file is a built-in function it is a good idea to not use it as a 
> variable name.
>
> for fn in files:
>    base, ext = os.path.splitext(fn)
>    if ext in ['.flac','.mp3','.m4a']:   ## CORRECTION removed *
>        #do some stuff if the someFile matches one of the items in the 
> list
>> Can it get any better ?  I was hoping fnmatch would *accept* a list
>> instead of a string ... but it didn't (frown).  I thought maybe:
>>
>> if fnmatch(someFile, ['*.flac','*.mp3','*.m4a']):
>>
>> But that didn't work.  Thanks in advance,
>>
>> Damon
>>
>> PS: just reading the conversations on this list is a little like
>> taking a python class (only the classes don't progress in any
>> particular order!).
>> _______________________________________________


-- 
Bob Gailer
Chapel Hill NC 
919-636-4239