[Tutor] single key ordered sequence
jervisau at gmail.com
Fri Jan 16 00:52:52 CET 2009
On Fri, Jan 16, 2009 at 10:39 AM, bob gailer <bgailer at gmail.com> wrote:
> Jervis Whitley wrote:
>> On Fri, Jan 16, 2009 at 9:15 AM, Kent Johnson <kent37 at tds.net <mailto:
>> kent37 at tds.net>> wrote:
>> On Thu, Jan 15, 2009 at 3:44 PM, Jervis Whitley
>> <jervisau at gmail.com <mailto:jervisau at gmail.com>> wrote:
>> > how about this:
>> > items = [(1,'a'),(1,'b'),(2,'a'),(3,'a'),
>> > (3,'b'),(4,'a'),(5,'a'),(5,'b'),(5,'c')]
>> > mydict = dict(items)
>> > items = [item for item in mydict.iteritems()]
>> That only coincidentally preserves order; the order of items in a
>> dictionary is, for practical purposes, unpredictable.
>> BTW [item for item in mydict.iteritems()] can be written as just
>> I realise that what you have said is true, however can you show me a case
>> > items = dict(items).items()
>> will not preserve order? Thanks.
> On my computer:
> >>> dict((('z', 1), ('y', 2))).items()
> [('y', 2), ('z', 1)]
> Bob Gailer
> Chapel Hill NC
Same on mine, thanks.
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