[Tutor] smptlib question

[Albert-jan Roskam]

Hi David and Tino,

Thanks! I will try this tonight when I'm back home from the office. It's interesting to see how you split up the code into several little functions. Maybe it's typical for a newbie (like myself) to have the tendency to put everything into one function, instead of letting each function have its own purpose.

Cheers!!
Albert-Jan

--- On Tue, 6/9/09, David <david at abbottdavid.com> wrote:

> From: David <david at abbottdavid.com>
> Subject: Re: [Tutor] smptlib question
> To: "Albert-jan Roskam" <fomcl at yahoo.com>
> Cc: "*tutor python" <tutor at python.org>
> Date: Tuesday, June 9, 2009, 2:13 AM
> Albert-jan Roskam wrote:
> > (sorry for posting this again, but something might
> have gone wrong)
> > 
> > Hi,
> > 
> > I made a very simple program to send everybody I know
> a change of address I am parsing the .msg files with another
> function, which returns a set called 'recipients'.
> > 
> > The code below works, but it displays all recipients
> in the 'to' field. That is, in the Nth iteration, N
> recipients are shown. So the first mail has one recipient in
> the 'to' field, the second mail has the first and the second
> recipient, and so forth. I only want one recipient to be
> shown in the 'to' field. It's ugly and since I have a lot of
> email addresses to parse (4 years worth of emails!), it
> would become a very long list.
> > 
> > Pointers, anyone?
> > 
> > Thanks!
> > Albert-Jan
> > Python 2.5, Windows XP
> > 
> > import smtplib, email.utils
> > from email.mime.text import MIMEText
> > 
> > msg = MIMEText("""Dear reader:\n\nblaaaaah blaah
> blaah.\nSincerely,\nThe dude""")
> > 
> > sender = 'ren at stimpy.com'
> > recipients = ['happyhappy at joy.com',
> 'you at eediot.com]
> > for no, recipient in enumerate(recipients):
> >     print "--> Sending message
> to: %s (%s of %s)" % (recipient, no+1, len(recipients))
> >     msg['To'] =
> email.utils.formataddr((recipient, recipient))
> >     print msg['To']
> >     msg['From'] =
> email.utils.formataddr(('Cool dude', sender))
> >     msg['Subject'] = 'Change of
> email address'
> > 
> >     server =
> smtplib.SMTP("mysmtpserver.isp.com")
> >     server.set_debuglevel(True)
> >     try:
> >     
>    server.sendmail(sender, [recipient],
> msg.as_string())
> >     finally:
> >         server.quit()
> > 
> > 
> >   
>    _______________________________________________
> > Tutor maillist  -  Tutor at python.org
> > http://mail.python.org/mailman/listinfo/tutor
> > 
> > 
> 
> Hi Albert,
> I got this to work;
> 
> #!/usr/bin/python
> 
> import smtplib, email.utils
> from email.mime.text import MIMEText
> from email.MIMEMultipart import MIMEMultipart
> from email.Utils import COMMASPACE, formatdate
> 
> def recipients():
>     recipients = ['happyhappy at joy.com',
> 'you at eediot.com]
>     for no, recipient in enumerate(recipients):
>         print "--> Sending message
> to: %s (%s of %s)" % (recipient, no+1, len(recipients))
>         message(recipient)
> 
> def message(recipient):
>     body = "Dear reader:\n\nblaaaaah blaah
> blaah.\nSincerely,\nThe dude"
>     send_mail([recipient], 'Change of email
> address', body)
> 
> 
> def send_mail(send_to, subject, text,
> server="mail.stimpy.com"):
>     send_from = "ren at stimpy.com"
>     msg = MIMEMultipart()
>     msg['To'] = COMMASPACE.join(send_to)
>     msg['Date'] = formatdate(localtime=True)
>     msg['From'] = send_from
>     msg['Subject'] = subject
>     msg.attach( MIMEText(text) )
>     smtp = smtplib.SMTP(server)
>     smtp.sendmail(send_from, send_to,
> msg.as_string())
>     smtp.close()
> 
> recipients()
> 
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