[Tutor] How do I do this in python?
denis.spir at free.fr
Thu Jun 11 13:19:53 CEST 2009
Le Thu, 11 Jun 2009 12:56:27 +0200,
The Green Tea Leaf <thegreentealeaf at gmail.com> s'exprima ainsi:
> My advice: "Learning Python" very nice book
> def show(*args):
> print args
> def show2(*args):
> for item in args:
> print "Blabla:",item
Well, it's not what the poster asked for: where are the (var) names?
> On Thu, Jun 11, 2009 at 03:43, Robert Lummis<robert.lummis at gmail.com> wrote:
> > I want to write a function that I can use for debugging purposes that
> > prints the values of whatever list of object references it is given as
> > arguments, without knowing in advance how many object references it
> > will be called with or what they might be. For example, the call:
> > show(a,b,c) would output the values of the arguments like this:
> > a = 3
> > b = 'john'
> > c = 'Monday'
> > while show (x) would output (for example):
> > x = 3.14
> > of course displaying whatever the actual current values are. For a
> > collection object it would make sense to output just the first few
> > values.
> > So within the 'show' function definition I have to somehow get a list
> > of the literal argument names it was called with and then use the
> > names as globals to get the values. How do I do that?
> > If this can't be done but there is a completely different way to
> > achieve a similar result, what is it?
> > I'm trying to learn python but it's a struggle because the
> > documentation is so dispersed. If there is a solution to this
> > question, what documentation could I have looked at to find it on my
> > own?
> > BTW I'm using python 3.01 if it matters.
> > --
> > Robert Lummis
> > _______________________________________________
> > Tutor maillist - Tutor at python.org
> > http://mail.python.org/mailman/listinfo/tutor
la vita e estrany
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