[Tutor] How do I do this in python?
denis.spir at free.fr
Thu Jun 11 17:58:54 CEST 2009
Le Thu, 11 Jun 2009 10:46:26 -0400,
Kent Johnson <kent37 at tds.net> s'exprima ainsi:
> On Wed, Jun 10, 2009 at 9:43 PM, Robert Lummis<robert.lummis at gmail.com>
> > I want to write a function that I can use for debugging purposes that
> > prints the values of whatever list of object references it is given as
> > arguments, without knowing in advance how many object references it
> > will be called with or what they might be. For example, the call:
> > show(a,b,c) would output the values of the arguments like this:
> > a = 3
> > b = 'john'
> > c = 'Monday'
> > while show (x) would output (for example):
> > x = 3.14
> Here is a pretty clean solution. It passes names rather than values,
> then looks the values up in the caller's stack frame. Written for
> Python 2.x but should work for 3.x if you change the prints.
> In : import sys
> In : def show(names):
> ....: frame = sys._getframe(1)
> ....: for name in names.split():
> ....: if name in frame.f_locals:
> ....: print name, '=', frame.f_locals[name]
> ....: else:
> ....: print name, 'not found'
la vita e estrany
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