I was playing around with eliminating duplicates in a list not using groupby. From the two solutions below, which is more "pythonic". Alternative solutions would be welcome. Thanks x=[1,1,1,3,2,2,2,2,4,4] [v for i,v in enumerate(x) if x[i]!=x[i-1] or i==0] [x[i] for i in range(len(x)-1) if i==0 or x[i]!=x[i-1]] output: [1, 3, 2, 4]