[Tutor] Handling Generator exceptions in Python 2.5
vinces1979 at gmail.com
Fri Jun 19 17:09:08 CEST 2009
*result = [(ListA[i] - ListB[i-1])/ListA[i] for i in range(len(ListA))*if
not ListA[i] == 0*]
will exclude any results where listA[i] is 0, if you still want these in the
you may want to use good'ol for statement instead of list comprehension
results = 
for x in range(len(listA)):
y = ListA[i] - ListB[i-1]
if not ListA[i] == 0:
y = y / ListA[i]
On Fri, Jun 19, 2009 at 8:55 AM, Joe Python <jopython at gmail.com> wrote:
> I have a generator as follows to do list calculations.
> *result = [(ListA[i] - ListB[i-1])/ListA[i] for i in range(len(ListA))]*
> The above generator, throws '*ZeroDivisionError*' exception if ListA[i] =
> Is there a way to say 'Don't divide by ListA[i] if its equal to 0 (within
> that statement)'.
> Sorry if this question sounds too stupid.
> Tutor maillist - Tutor at python.org
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the Tutor