[Tutor] "if clause" in list comprehensions.

[Albert-Jan Roskam]

Is the if-else (esp. 'else') in a list comprehension specific for Python 3.x? Or did I miss something?

Cheers!!
Albert-Jan

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Before you criticize someone, walk a mile in their shoes, that way 
when you do criticize them, you're a mile away and you have their shoes! 
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--- On Tue, 10/20/09, Alan Gauld <alan.gauld at btinternet.com> wrote:

> From: Alan Gauld <alan.gauld at btinternet.com>
> Subject: Re: [Tutor] "if clause" in list comprehensions.
> To: tutor at python.org
> Date: Tuesday, October 20, 2009, 12:29 AM
> Ooops, hit send by mistake...
> 
> "vince spicer" <vinces1979 at gmail.com>
> wrote
> 
> >> Lambda can save the day to keep everything on one
> line, and leave variable
> >> type the same:
> >> 
> >> mylist = ['John', 'Canada', 25, 32, 'right']
> >> new_list = [(lambda y: y.upper() if hasattr(y,
> 'upper') else y)(a) for a in
> >> mylist ]
> >> 
> >> >>  ['JACK', 'CANADA', 25, 32,
> 'RIGHT']
> 
> In what way does lambda help?
> 
> new_list = [y.upper() if hasattr(y, 'upper') else y for y
> in mylist]
> 
> does exactly the same and is shorter.
> 
> lambda helps if you want to pass a function object around
> but
> defining it and immediately calling it means it can be
> replaced
> directly by the expression within the lambda.
> 
> But using hasattr() still has the problem of failing if
> upper is not a
> callable attribute (or does something radical like
> exiting)
> 
> 
> -- Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/ 
> 
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