[Tutor] Pack as HEX question
Tom Green
xchimeras at gmail.com
Sat Oct 24 21:36:43 CEST 2009
This is what I have so far,
import struct
EncryptString="313B372C2E2C63362E2128"
XorKey="41424344"
key = struct.unpack("d", XorKey)
num_ints = len(EncryptString)/11
data = struct.unpack("%dd"% num_ints,EncryptString)
The above code generates an error the my string must be a string length of
16
When you say I need to determine the number of ints in my data i.e.
EncryptString that value would be 11 right?
I appreciate your help.
Mike.
On Sat, Oct 24, 2009 at 2:41 PM, ALAN GAULD <alan.gauld at btinternet.com>wrote:
> > Take the 4 byte XOR key. If I convert them to int with Base 16
> > it takes the 4 and converts it to 0x34 when I in turn I actually need
> 0x41.
>
> OK, thats because int is for converting strings. You need to use
> struct.unpack
> to convert the 4 bytes into an int.
>
> You also need to figure out how many ints you have in your data and
> construct a format string with that many ints to struct unpack the data.
>
> Them apply the xor to each int using the key
>
> something like
>
> key = struct.unpack("d", keydata)
> num_ints = len(raw_data)/len(int)
> data = struct.unpack("%dd" % num_ints, raw_data)
>
> result = [n^key for n in data]
>
> (untested pseudo code!)
>
> HTH,
>
> Alan G.
>
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