[Tutor] elif statement

[Adam Bark]

On 11/08/10 02:34, Sudarshana Banerjee wrote:
> Hi: I am trying to teach myself Python, and am stuck at the 
> indentation with the elif statement.
>
> This is what I am trying to type (as copied from the textbook):
>
> x=3
> if x==0:
>     print "x is 0"
> elif x&1 ==1:
>     print "x is a odd number"
> elif x&1==0: -- Line 6
>     print "x is a even number"
>
> If I am combining the if and the print statement, then the elif 
> statement is in the next line, and all is well with the world. If 
> however, I write the print as a separate statement, I am getting a 
> syntax error after I press Enter after keying the first elif statement.
>
> >>> x=3
> >>> if x==0:
> print x
> elif x==2:

Here you have indented the elif statement but it should be at the same 
level as the if:
 >>> x=3
 >>> if x==0:
...     print x
... elif x==2:
...     print "something else"
...
 >>>


> SyntaxError: invalid syntax
>
> Again:
> >>> x=3
> >>> if x==2: print x
> elif x&1 == 1: print 'x is odd'
> >>> elif x&1 ==0: print 'x is even'
> SyntaxError: invalid syntax

I'm not sure what's going on here but the second elif is being 
interpreted separate to the rest of the if statement hence a SyntaxError:
 >>> elif x&1 == 0: print "x is even"
   File "<stdin>", line 1
     elif x&1 == 0: print "x is even"
        ^
SyntaxError: invalid syntax

This works:
 >>> if x==2: print x
... elif x&1 == 1: print 'x is odd'
... elif x&1 ==0: print 'x is even'
...
x is odd


>
> If I am pressing two Enters, the code executes; so I have a elif 
> without a if, and again, a syntax error. What am I not doing right?
>
> Thank you.
>
> Sudarshana.
HTH,
Adam.


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