[Tutor] exercise problem
Roelof Wobben
rwobben at hotmail.com
Fri Aug 27 17:05:43 CEST 2010
Hello,
My first try :
def add_vectors(u, v):
"""
>>> add_vectors([1, 0], [1, 1])
[2, 1]
>>> add_vectors([1, 2], [1, 4])
[2, 6]
>>> add_vectors([1, 2, 1], [1, 4, 3])
[2, 6, 4]
>>> add_vectors([11, 0, -4, 5], [2, -4, 17, 0])
[13, -4, 13, 5]
"""
teller=1
getal1=0
getal2=0
while teller < len(u):
getal1 = getal1 + u[teller,0] + v[teller,0]
getal2 = getal2 + v[teller,1] + v[teller,1]
teller=teller+1
return uitkomst2[getal1, getal2]
uitkomst= []
vector= [[1,0], [1,1]]
v=vector[0]
u=vector[1]
uitkomst = add_vectors[u,v]
But now I get this error message :
Traceback (most recent call last):
File "C:\Users\wobben\workspace\oefeningen\src\test.py", line 27, in <module>
uitkomst = add_vectors[u,v]
TypeError: 'function' object is not subscriptable
So it seems that I can't use vectors as a variable in a function.
Roelof
From: rwobben at hotmail.com
To: tutor at python.org
Subject: RE: [Tutor] exercise problem
Date: Fri, 27 Aug 2010 14:38:23 +0000
Oke,
That's also the point Alan is making.
I try now to make the function and puttting it on this maillist if it's ready.
Maybe I can learn more about efficient progamming or better way to do this.
Roelof
> From: steve at pearwood.info
> To: tutor at python.org
> Date: Sat, 28 Aug 2010 00:15:15 +1000
> Subject: Re: [Tutor] exercise problem
>
> On Fri, 27 Aug 2010 08:23:06 pm Roelof Wobben wrote:
> > > > Write a function add_vectors(u, v) that takes two lists of
> > > > numbers
> [...]
> > My new idea is that u is the number which must be calculated and v is
> > the vector which containts the outcome or u is the outcome of the
> > first numbers and v the outcome of the second numbers.
>
> If you had a function called "add_numbers(x, y)", you would say that x
> and y are the numbers which are to be added. If you have a function
> called "add_vectors(u, v)", then u and v are the vectors to be added.
> Perhaps this example will help:
>
>
> u = [1, 10, 100]
> v = [2, 11, 111]
> add_vectors(u, v)
> => [3, 21, 211]
>
>
>
>
> --
> Steven D'Aprano
> _______________________________________________
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