[Tutor] Help return a pattern from list

[Shashwat Anand]

On Mon, Jul 5, 2010 at 11:58 PM, Shashwat Anand <anand.shashwat at gmail.com>wrote:

>
>
> On Mon, Jul 5, 2010 at 11:24 PM, Vineeth Rakesh <vineethrakesh at gmail.com>wrote:
>
>> Hello all,
>>
>> Can some one help me to return a special pattern from a list.
>>
>> say list =
>> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
>>
>
> One suggestion. Don't name a list as list. Use l or List or any other
> variable name. list is one of the syntax in python.
>
>
>>
>> now say I just need to return the files with .mp3 extension. How to go
>> about doing this?
>>
>
> >>> list =
> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
> >>> [i for i in list if i[-4:] == '.mp3']
> ['something1.mp3', 'something2.mp3']
>
> or may be ,
> >>> [i for i in list if os.path.splitext(i)[0] == '.mp3']  # If you want to
> deal with file extentions, that is.
>

Oops, sorry for the typo.
It'll be ,
>>> [i for i in list if os.path.splitext(i)[1] == '.mp3']


>  For smaller case string is good, for obscure patter, you can try regex
> module.
>
>  ~l0nwlf
>
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