[Tutor] Order Of Operations Question
Evert Rol
evert.rol at gmail.com
Wed Jul 28 12:11:41 CEST 2010
Sorry, forgot to reply-to-all:
I don't know the book nor the exercise, but see my comments interspersed in the code, and a few general remarks at the bottom
> From a practice exercise in Building Skills In Python page 64 I'm
> working on How Much Does The Atmosphere Weigh? Part 1:
> To check it states that the answer should be app. 10**18kg However,
> and I've checked to make sure that the math I've layed out matches up
> with the texts, I get 5.07360705863e+20
>
> In the code I have broken the order of operations down to more
> parenthetical, and tried outright, but see nothing obvious about how
> it's strung together. If anyone has had a similar experience with the
> problem given, or see anything blatantly obvious I've done wrong with
> the ordering of operations. I tried to include as much of the
> problem(formulas are just above variables they're used in) as comments
> as possible.
>
> import math
> def atmosphereWeight():
> pi = math.pi
> """Air Pressure (at sea level) P0. This is the long-term average.
> P0 = 1.01325 × 10**5"""
> airPressCLevl = 1.01325*(10**5)
> gravity = 9.82
> """We can use g to get the kg of mass from the force of air
> pressure P0. Apply the acceleration of gravity
> (in m/sec2) to the air pressure (in kg · m/sec2). This result is
> mass of the atmosphere in kilograms per
> square meter (kg/m2).
> Mm2 = P0 × g"""
> masAtmoInKgPerSqM = airPressCLevl * gravity
Simply from looking at the units left and right of the equality sign, you'll need to *divide* by g, not multiply: [kg] = [kg m / s^2] / [m / s^2]
> """Given the mass of air per square meter, we need to know how
> many square meters of surface to apply
> this mass to. Radius of Earth R in meters, m. This is an average
> radius; our planet isn’t a perfect sphere.
> R = 6.37 × 10"""
> avgRadiusEarth = 6.37 * (10**6)
> """The area of a Sphere.
> A = 4πr2"""
> areaSphere = 4 * pi * (avgRadiusEarth**2)
> """Mass of atmosphere (in Kg) is the weight per square meter,
> times the number of square meters
> Ma = P0 × g × A"""
> masEarthAtmoInKgPerSqM = airPressCLevl * gravity * areaSphere
ditto here: divide by gravity, not multiply by it.
> print(masEarthAtmoInKgPerSqM)
>
> atmosphereWeight()
Few general remarks:
- the standard way of writing numbers with a power of ten in code is something like 1.01325e5. I guess this is also easier/quicker to execute (not that this code is time-critical, but in general)
- why do you assign masTmoInKgPerSqM, then later not use it when calculating masEarthAtmoInKgPerSqM?
- just use math.pi when calculating areaSphere, instead of "pi = math.pi" and then later using pi. For me, that's just as clear.
- no need to put parentheses around powers; they are evaluated before the multiplication (unless this is what you meant by "to more parenthetical"
- try indenting the comments as well; more readable
Probably not all of the above are necessary, if you wrote this for debugging your problem, but they're just some thoughts that occurred to me.
Enjoy your calculations.
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