[Tutor] Process list elements as consecutive pairs

[Emad Nawfal (عمـ نوفل ـاد)]

On Fri, Mar 5, 2010 at 1:03 PM, Wayne Werner <waynejwerner at gmail.com> wrote:

> On Fri, Mar 5, 2010 at 11:56 AM, Rüdiger Wolf <
> rudiger.wolf at throughputfocus.com> wrote:
>
>> Hi
>>
>> I am trying to Process list elements as consecutive pairs  into
>> consecutive pairs.
>> Any pythonic suggestions?
>>
>> listin = [1,2,3,4,5,6,7,8,9,10]
>> I want to process as consecutive pairs
>> 1,2
>> 3,4
>> 5,6
>> 7,8
>> 9,10
>>
>
> for x in xrange(0, len(listin), 2):
>     print listin[x], listin[x+1]
>
> - that's probably how I'd do it anyway.
>
> HTH,
> Wayne
>
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> Here is a general solution that I also took from the Tutor list some time
ago. It allows you to have consequences of (any) length.

>>> def makeVectors(length, listname):
...     """takes the length of the vector and a listname returns vectors"""
...     vectors = (listname[i:i+length] for i in
range(len(listname)-length+1))
...     return vectors
...
>>> myList = [1,2,3,4,5,6]

>>> bigrams = makeVectors(2, myList)
>>> bigrams
<generator object <genexpr> at 0xb7227e64>
>>> for bigram in bigrams: print bigram
...
[1, 2]
[2, 3]
[3, 4]
[4, 5]
[5, 6]
>>>


-- 
لا أعرف مظلوما تواطأ الناس علي هضمه ولا زهدوا في إنصافه كالحقيقة.....محمد
الغزالي
"No victim has ever been more repressed and alienated than the truth"

Emad Soliman Nawfal
Indiana University, Bloomington
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