[Tutor] if statement

[Vince Spicer]

On Tue, Nov 2, 2010 at 1:07 PM, Glen Clark <glenuk at gmail.com> wrote:

> sorry:
>
> NumItems = int(input("How many Items: "))
>
>
> Entries = []
> for In in range(0,NumItems):
>   Entries.append("")
>
>
>
> for In in range(0,NumItems):
>   Entries[In]=str(input("Enter name " + str(In+1) + ": "))
>
>
> for In in range(0,NumItems):
>   print(Entries[In])
>
> confirmed = int(input("Are you happy with this? (y/n): ")
>
> if confirmed == "y":
>   for In in range(0,NumItems):
>      print(Entries[In] + ": " + str(In))
>   change = int(input("Which item would you like to change: ")
>   Entries[change]=str(input("Please enter a nem name: ")
> else:
>    #do nothing
>
> print(Entries)
>
> On Tue, 2010-11-02 at 15:05 -0400, Alex Hall wrote:
> > On 11/2/10, Glen Clark <glenuk at gmail.com> wrote:
> > >  File "/home/glen/workspace/test.py", line 19
> > >     if confirmed == "y":
> > >                        ^
> > > SyntaxError: invalid syntax
> > >
> > > Why does this not work??? PyDev says "Expected:else"
> > It may help to see the rest of the file, or at least more of the code
> > surrounding this statement.
> > >
> > > _______________________________________________
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>
>
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confirmed = int(input("Are you happy with this? (y/n): ")

You are missing a ) that the end of this line to close the int

-- 
Vince Spicer


-- 
Sent from Ubuntu
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