[Tutor] Rounding a Python float to the nearest half integer

[Sithembewena Lloyd Dube]

Thanks Shantanoo, finally got the hang of this.

2010/10/11 शंतनू (Shantanoo) <shantanoo at gmail.com>

> ===
> round(...)
>     round(number[, ndigits]) -> floating point number
>
>     Round a number to a given precision in decimal digits (default 0
> digits).
>     This always returns a floating point number.  Precision may be
> negative.
> ===
>
> >>> round(1.23423,2)
> 1.23
> >>> round(1.23623,2)
> 1.24
>
>
> HTH.
>
> On Mon, Oct 11, 2010 at 13:51, Sithembewena Lloyd Dube <zebra05 at gmail.com>wrote:
>
>> Thanks everyone.
>>
>>
>> On Fri, Oct 8, 2010 at 11:44 PM, Wayne Werner <waynejwerner at gmail.com>wrote:
>>
>>> On Fri, Oct 8, 2010 at 7:58 AM, Sithembewena Lloyd Dube <
>>> zebra05 at gmail.com> wrote:
>>>
>>>> I realise that one cannot have a half integer :) I meant how would one
>>>> round off to the first decimal nearest to either 0.5, or a whole number.
>>>>
>>>> Ugh...does anyone get what I'm trying to articulate? :)
>>>
>>>
>>> sample input/output cases are always useful.
>>>
>>> -Wayne
>>>
>>
>>
>>
>> --
>> Regards,
>> Sithembewena Lloyd Dube
>> http://www.lloyddube.com
>>
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>


-- 
Regards,
Sithembewena Lloyd Dube
http://www.lloyddube.com
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